a^2+10a-35=5a

Solution for a^2+10a-35=5a equation:

a^2+10a-35=5a

We move all terms to the left:

a^2+10a-35-(5a)=0

We add all the numbers together, and all the variables

a^2+5a-35=0

a = 1; b = 5; c = -35;
Δ = b2-4ac
Δ = 52-4·1·(-35)
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{165}}{2*1}=\frac{-5-\sqrt{165}}{2}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{165}}{2*1}=\frac{-5+\sqrt{165}}{2}
$